4^2x+4^(2+x)-80=0

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Solution for 4^2x+4^(2+x)-80=0 equation: 



4^2x+4^(2+x)-80=0

We add all the numbers together, and all the variables

4^2x+4^(x+2)-80=0

We move all terms containing x to the left, all other terms to the right

4^2x+4^(x+2)=80

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